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 18 digits (Posted on 2012-01-12)
Given 5 twos, 4 threes, 6 fives and 3 sevens create a multiplication problem , partial products included. I believe the solution is unique.

 No Solution Yet Submitted by Ady TZIDON Rating: 3.0000 (2 votes)

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 re(3): a solution + one more | Comment 4 of 5 |
(In reply to re(2): a solution by Dej Mar)

Dear  DejMar,

It is true, that I've erred. I cannot say that I  regret it  , since my misgiving introduced 2 beautiful solutions of another version of my original puzzle.

I ERRED ELSEWHERE:  just cfhange the title to  "24 digits"and look for a unique (I believe- ??) solution. As you've noticed - and I did not-  3 digit multicand and 3 digit multiplier, with three 4 digit "partial products" and a 6 digits result gives 24 digits.

Sorry about imposing this extra task on you - and it is D4- BUT LET  US CONSIDER IT A TEAM WORK - jointly creating a 3 level  puzzle of 24 prime digits.

 Posted by Ady TZIDON on 2012-01-15 00:45:12

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