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S.o.d . of s.o.d ,,, (Posted on 2012-02-21) Difficulty: 2 of 5
Given a 2011 digit number, divisible by 9.
Let x be the sum of its digits and y the sum of the digits of x.

Find z, sum of the digits of y .

See The Solution Submitted by Ady TZIDON    
Rating: 4.0000 (2 votes)

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Solution Digit Comment 4 of 4 |
The sum of the digits of the first number has to be divisible by 9. If it is 2011 9's, then x=18099. Therefore, 9<=x<=18099. If x=9999, then y=36. Therefore, 9<=y<=36. The numbers 9, 18, 27, and 36 add up to 9. Therefore, z=9.
  Posted by Math Man on 2012-03-02 20:48:59
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