All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Multi-Birth Convention (Posted on 2012-01-05) Difficulty: 3 of 5
At a convention of pairs of twins and sets of triplets, there were 9 sets of twins and 6 sets of triplets, each set being from a different family. Each twin shook hands with all the twins except his or her sibling and with half the triplets. Each triplet shook hands with all the other triplets except his or her siblings and with half the twins.

How many handshakes took place all together?

  Submitted by Charlie    
Rating: 4.0000 (2 votes)
Solution: (Hide)
twin-twin: 18*16/2 = 144
twin-triplet: 18*9=162
triplet-triplet: 18*15/2=135

total = 144 + 162 + 135 = 441

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionI think this works.Jer2012-01-05 12:30:13
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information