Consider an infinite chessboard. Each square contains either a 1 or an X in some pattern. (X can be any real number but for a given board, all the X's are the same.)
Each square with an X on it has weight equal to zero.
Each square with a 1 on it has a weight of 1 + N*X where N is the total number of X's on the 8 surrounding squares.
For a given value of X, find a way of tiling the board with the highest average weight per square.
Inspired by various Tower Defense games.
(In reply to
re: Shaky ground? You misunderstand. by Jer)
Yes, upon reading Steve Herman I clearly did misunderstand. I was looking at a "1" as having neighbouring "X"s somewhat akin to the solitaire "Minefield" game.

Posted by brianjn
on 20120208 21:01:28 