Remember
this Magic Die? I've got another magic die, which is nsided (with numbers 1 through n on its faces) and where n=0 mod 8.
After the first roll, if an odd number appears on the top face, all odd numbers on the die are squared. If an even number appears on the top face, all odd numbers are increased by 3 and then all numbers are halved and then squared.
If the given die changes as described and assuming a perfectly balanced die, what is the probability that the number appearing on the second roll of the die is 1 mod 8? How about 4 mod 8?
die faces [mod 8]
1 2 3 4 5 6 7 0  initial
1 2 1 4 1 6 1 0  after 1st roll, odd
4 1 1 4 0 1 1 0  after 1st roll, even
After 1st roll
0 mod 8 : 3/16
1 mod 8 : 8/16
2 mod 8 : 1/16
4 mod 8 : 3/16
6 mod 8 : 1/16
For the second roll...
0 is even, halved then squared it is still 0 mod 8
1 is odd, squared it is still 1 mod 8
2 is even, halved then squared it is 1 mod 8
4 is even, halved then squared it is still 4 mod 8
6 is even, halved then squared it is 1 mod 8
After 2nd roll
0 mod 8 : 3/16
1 mod 8 : 8/16 + 2/16 = 10/16 = 5/8
4 mod 8 : 3/16

Posted by Dej Mar
on 20120228 23:25:10 