-1/1 = 1/-1
⇒ √(-1/1) = √(1/-1) (taking the square root of both sides)
⇒ √(-1)/√1 = √1/√(-1)
⇒ i/1 = 1/i
⇒ i/2 = 1/(2i)
⇒ i/2 + 3/(2i)= 1/(2i) + 3/(2i)
⇒ i(i/2 + 3/(2i))= i(1/(2i) + 3/(2i))
⇒ i²/2 + (3i)/(2i)= i/(2i) + (3i)/(2i)
⇒ (-1)/2 + 3/2 = 1/2 + 3/2
⇒ 1=2

Can you spot the flaw in the above proof?

(In reply to You can't do that by Jer)

There's a typo in your comment.

i/1 = i, not 1

Posted by Charlie on 2012-09-27 11:56:04