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A frugal sequence (Posted on 2012-09-14) Difficulty: 3 of 5
Find the longest(?) string of consecutive frugal numbers.

Def: A frugal number is a natural number that has more digits than the number of digits in its prime factorization (including exponents). For example, 128=2^7 and 29282=2*11^4

See The Solution Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

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Some Thoughts re: computer results so far | Comment 7 of 13 |
(In reply to computer results so far by Charlie)

A variation on the program, allowed to progress quite far, beyond a half-billion, found a sequence of 4 beginning at 179,210,312:

179210312 = 2^3 * 4733^2
179210313 = 3^5 * 97 * 7603
179210314 = 2 * 29 * 37^3 * 61
179210315 = 5 * 79^2 * 5743


  Posted by Charlie on 2012-09-14 18:01:25
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