All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
A Pythagorean piglet (Posted on 2012-09-22) Difficulty: 3 of 5

Finding solutions to x2- b2=b2-1 is a bit too easy these days, so let b itself be the multiple of a square, say, yz2

For both y>1 and z>1, prove that y is not a square, or find a counter-example.

See The Solution Submitted by broll    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Oinking solution. | Comment 3 of 4 |
(In reply to re: Oinking solution. by broll)

Ok you you are considering (az)^2 to be the multiple of a square where y=a^2, even though it is also a square itself.  Of course it is and that was my mistake.


  Posted by Jer on 2012-09-26 12:41:34

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information