Finding solutions to x2- b2=b2-1 is a bit too easy these days, so let b itself be the multiple of a square, say, yz2
For both y>1 and z>1, prove that y is not a square, or find a counter-example.
(In reply to
re(2): Oinking solution. by Jer)
Jer, I owe you an apology because having re-read the problem to prepare the solution, I - errm - came up with your answer.
Rearranging the factors slightly gives:
2*7801^2*(5^4)-1=275807^2, with the power of y a square and of z a 4th power, as was required by the problem.
2373672716981597^2*2*(5^4)-1=83922003724759193^2 is also a solution, along the same lines.
Edited on December 23, 2012, 11:48 pm
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Posted by broll
on 2012-12-23 09:12:26 |
re(3): Oinking solution.
