All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
Poker Game (Posted on 2012-09-07) Difficulty: 3 of 5
A game of poker is played where there are 3 players and each player starts with 2 coins. At the beginning of each hand, every player bets 1 coin and the winner of the hand gets his own coin back in addition to all the bets placed by the other players (for example, in the case of 3 players each betting 1 coin, the winner will receive 2 coins in profit). Now assume the winner of a hand is determined at random (e.g. with 3 players the chance of winning is 1/3). Also assume that once a player reaches 0 coins he/she is out. Determine the expected number of hands that will be played in the match.

No Solution Yet Submitted by Chris, PhD    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Don't play poker while drunk (spoiler) | Comment 1 of 4
With probability 1/3, the same player wins the 1st two hands, and the game is over after 2 hands.

Otherwise, with probability 2/3, two different players win the first two hands, and the third is eliminated.  The coins are distributed 3-3, and now we have a classical one-dimensional random "drunkard's" walk with absorbing endpoints (the game ends when a player has 0 or 6 coins) and probability 1/2 of gaining or losing 1 coin on each hand.  I happen to know that the expected number of steps from this point is the product of the number coins held by each player, which is 3*3 = 9.  So, the answer to the problem is 2 + (2/3)*9 = 8 expected hands.  Final answer.

The number of expected steps in the two player game (9) could have been calculated.  Let F(x) be the expected remaining steps if you have x coins out of 6. 

F(0) = 0
F(1) = 1 + 1/2(F(0) + F(2)) = 1+ F(2)/2
F(2) = 1 + 1/2(F(1) + F(3))
F(3) = 1 + 1/2(F(2) + F(4))
but F(2) = f(4), so F(3) = 1 + F(2)

This gives F(2) = 1 + 1/2((1+ F(2)) + (1 + F(2)/2))
Simplifying gives F(2) = 8

F(0) = 0
F(1) = 5  (note, this is 5*1)
F(2) = 8  (note, this is 4*2)
F(3) = 9  (note, this is 3*3)

  Posted by Steve Herman on 2012-09-07 12:09:03
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (2)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2020 by Animus Pactum Consulting. All rights reserved. Privacy Information