(In reply to
re: As years go by... by Ady TZIDON)
Because (ab) is a factor of (a^nb^n) in the specified cases.
Write X as (ab) and Y as (cd) choosing appropriate integers, so that we know that X divides (a^nb^n) and Y divides (c^nd^n)
All that then needs to be done is to multipy out (a^nb^n) (c^nd^n) and we have a readymade Perplexus problem suitable for any year, XY, of our choice.
Edited on January 6, 2013, 10:33 am

Posted by broll
on 20130106 10:33:14 