Find the sum of the fiftieth powers of all sides and diagonals of a regular 100gon inscribed in a circle of radius R.
Let R=1/2 (so the diagonals = 1)
Then the sum is 50+[100*sin(pi/100)^50], with the expression in square brackets being of the order of 10^76. It's not obvious to me how these highly incommensurate numbers could be added with any meaningful exactitude.
This difficulty is further enhanced if the 'proper diagonals' (i.e. including all those not passing though the centre) are taken since there are 4850 of those, and they are of varying lengths.
Edited on December 11, 2012, 2:12 am

Posted by broll
on 20121130 04:52:27 