Find a natural number n such that n+1, n+11, n+111 are all primes.

Trying **2 as a first even number** we get an **answer.**

To qualify for d1 or d2 I will rephrase the question:

Prove that there is **only one natural number** **n** such that n+1, n+11, n+111 are all primes.

SOLUTION:

**FOR n>2 t**

The three addends are distinct members of the set **(1,2,3)** therefore at least one of them is divisible by 3 and therefore cpomposite.