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 Age Ascertainment II (Posted on 2013-02-01)
```       +-----+-----+
|  A  |     |
+-----+-----+-----+
|  B  |     |
+-----+-----+
```
The ages of Ambrose, Brandon and Chester can be related to the diagram above so that when just one digit is written in each box:
1. A across is Ambrose's age in years.
2. A down is the sum of Ambrose's and Brandon's age in years.
3. B across is the sum of Ambrose's age, Brandon's age and Chester's age in years.
4. Two of Ambrose, Brandon and Chester are the same age in years.
Who is a different age in years from the other two?

 No Solution Yet Submitted by K Sengupta Rating: 1.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 all solutions | Comment 2 of 4 |
C is the odd one =any non-zero one-digit  number of yearS
A=B= TEN OR TWENTY OR THIRTY OR FORTY
SO:
4*9=36
THIRTY SIX POSSIBLE TRIPLETS (A,B,C)

ERROR :

IN THIS POST  B & C SHOULD BE INTERCHANGED
SEE MY CORRECTION- after Charlie's remark

Edited on February 1, 2013, 4:04 pm
 Posted by Ady TZIDON on 2013-02-01 12:32:07

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