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Age Ascertainment II (Posted on 2013-02-01) Difficulty: 1 of 5
       +-----+-----+
       |  A  |     |
 +-----+-----+-----+
 |  B  |     |      
 +-----+-----+
The ages of Ambrose, Brandon and Chester can be related to the diagram above so that when just one digit is written in each box:
  1. A across is Ambrose's age in years.
  2. A down is the sum of Ambrose's and Brandon's age in years.
  3. B across is the sum of Ambrose's age, Brandon's age and Chester's age in years.
  4. Two of Ambrose, Brandon and Chester are the same age in years.
Who is a different age in years from the other two?

No Solution Yet Submitted by K Sengupta    
Rating: 1.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: all solutions | Comment 3 of 4 |
(In reply to all solutions by Ady TZIDON)

If A=B=10, for example, then A+B would be 20 (that is, Ambrose and Brandon). But Ambrose  (A across) is supposed to start with the same digit as Ambrose+Brandon (A down).
  Posted by Charlie on 2013-02-01 14:14:39

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