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Age Ascertainment II (Posted on 2013-02-01) Difficulty: 1 of 5
       +-----+-----+
       |  A  |     |
 +-----+-----+-----+
 |  B  |     |      
 +-----+-----+
The ages of Ambrose, Brandon and Chester can be related to the diagram above so that when just one digit is written in each box:
  1. A across is Ambrose's age in years.
  2. A down is the sum of Ambrose's and Brandon's age in years.
  3. B across is the sum of Ambrose's age, Brandon's age and Chester's age in years.
  4. Two of Ambrose, Brandon and Chester are the same age in years.
Who is a different age in years from the other two?

No Solution Yet Submitted by K Sengupta    
Rating: 1.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution re: all solutions CORRECTED Comment 4 of 4 |
(In reply to all solutions by Ady TZIDON)

B  is the odd one =any non-zero one-digit  number of yearS

A=C= TEN OR TWENTY OR THIRTY OR FORTY
SO:
4*9=36
THIRTY SIX POSSIBLE TRIPLETS (A,B,C)

IN mY PREVIOUS POST B & C SHOULD BE INTERCHANGED

  Posted by Ady TZIDON on 2013-02-01 16:02:24
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