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Apartment Allotment (Posted on 2013-02-06) Difficulty: 1 of 5
Avery , Blake , Clark and Doyle each live in an apartment. Their apartment are arranged like this :
          +---+---+---+---+
          | A | B | C | D |  --> East
          +---+---+---+---+
  1. One of the four is the landlord.
  2. If Clark's apartment is not next to Blake's apartment, then the landlord is Avery & lives in apartment A.
  3. If Avery's apartment is east of Clark's apartment, then the landlord is Doyle and lives in apartment D.
  4. If Blake's apartment is not next to Doyle's apartment, then the landlord is Clark and lives in apartment C.
  5. If Doyle's apartment is east of Avery's apartment, then the landlord is Blake and lives in apartment B.
Who is the landlord?

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Two approaches (spoiler) | Comment 2 of 7 |
I agree with Ady.  The only solution is DACB.  I solved this by forming the contrapositives of statements 2 - 5, figuring that 3 or 4 of the following predicates need to be true
  2. C is next to B
  3. A is west of C
  4. B is next to D
  5. D is west of A
and then logicking out that 4 was false.

But it is almost easier just to list the 24 possible combinations

ABCD -- This makes both B & C the landlord, which contradicts 1
ABDC -- This makes both A & B the landlord, which contradicts 1
ACBD -- contradicts 5
ACDB -- contradicts 5
ADBC -- contradicts 5
ADCB -- contradicts 4
BACD -- contradicts 2
BADC -- contradicts 2
BCAD -- contradicts 4
BCDA -- contradicts 3
BDAC -- contradicts 2
BDCA -- contradicts 2
CABD -- contradicts 2
CADB -- contradicts 2
CBAD -- contradicts 4
CBDA -- contradicts 3
CDAB -- contradicts 2
CDBA -- contradicts 2
DABC -- contradicts 4
DACB -- solution
DBAC -- contradicts 2
DBCA -- contradicts 3
DCAB -- contradicts 2
DCBA -- contradicts 3

Good puzzle.  Not a D1.

  Posted by Steve Herman on 2013-02-06 12:45:28
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