All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Seating Singularity (Posted on 2013-02-25)
Mr and Mrs Alden , Mr and Mrs Brent , Mr and Mrs Crown , Mr and Mrs Drake were seated around a table.

Their chairs were arranged around the square table like this:
```
a   b
+---+---+---+
|   |   |   |
h +---+---+---+ c
|   |   |   |
g +---+---+---+ d
|   |   |   |
+---+---+---+
f   e
```
For example, persons sitting at positions b and c are considered next to each other.
1. The person sitting across from Mrs Alden was a man who sat on Mr Brent's immediate left.
2. The person sitting on Mrs Crown's immediate left was a man who sat across from Mr Drake.
3. Only one couple did not sit next to each other & this couple did not sit across from each other.
Which couple did not sit next to each other?

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 computer solution Comment 1 of 1

DECLARE FUNCTION opposite! (x!)
DECLARE SUB permute (a\$)
CLS
a\$ = "ABCDabcd": h\$ = a\$
DO
MrsAlden = INSTR(a\$, "a")
tst = opposite(MrsAlden)
MrBrent = tst - 1: IF MrBrent < 1 THEN MrBrent = MrBrent + 8
IF MID\$(a\$, MrBrent, 1) = "B" AND MID\$(a\$, tst, 1) = UCASE\$(MID\$(a\$, tst, 1)) THEN
MrsCrown = INSTR(a\$, "c")
tst = MrsCrown + 1: IF tst > 8 THEN tst = tst - 8
IF MID\$(a\$, tst, 1) = UCASE\$(MID\$(a\$, tst, 1)) THEN
MrDrake = opposite(tst)
IF MID\$(a\$, MrDrake, 1) = "D" THEN
IF LEFT\$(a\$, 2) < MID\$(a\$, 3, 2) THEN
IF LEFT\$(a\$, 2) < MID\$(a\$, 5, 2) THEN
IF LEFT\$(a\$, 2) < MID\$(a\$, 7, 2) THEN
MrAlden = INSTR(a\$, "A")
tst = ABS(MrAlden - MrsAlden)
IF tst = 1 OR tst = 7 THEN adjCt = adjCt + 1: adj(1) = 1
MrsBrent = INSTR(a\$, "b")
tst = ABS(MrBrent - MrsBrent)
IF tst = 1 OR tst = 7 THEN adjCt = adjCt + 1: adj(2) = 1
MrCrown = INSTR(a\$, "C")
tst = ABS(MrCrown - MrsCrown)
IF tst = 1 OR tst = 7 THEN adjCt = adjCt + 1: adj(3) = 1
MrsDrake = INSTR(a\$, "d")
tst = ABS(MrDrake - MrsDrake)
IF tst = 1 OR tst = 7 THEN adjCt = adjCt + 1: adj(4) = 1
FOR i = 1 TO 4
NEXT
mate\$ = MID\$(a\$, opp, 1)
PRINT a\$, nadj\$: ct = ct + 1
END IF
END IF
END IF
END IF
END IF
END IF
END IF
END IF
permute a\$
LOOP UNTIL a\$ = h\$
PRINT ct

FUNCTION opposite (x)
SELECT CASE x
CASE 1
opposite = 6
CASE 2
opposite = 5
CASE 3
opposite = 8
CASE 4
opposite = 7
CASE 5
opposite = 2
CASE 6
opposite = 1
CASE 7
opposite = 4
CASE 8
opposite = 3
END SELECT
END FUNCTION

finds

`positionsabcdefgh--------AabBCDdc      c`

where capital letters are the men identified by last initial and women by lower-case letters.

So as not to include rotations, only the solution where the content of positions a and b is lower than the content of any other side of the table is shown.

Going clockwise as seen from above has the effect that being to someone's left means being to the right on the above scheme except when wrapping around the end to the beginning.

The letter to the right is the initial of the couple not sitting next to each other. Thus it is the Crowns who did not sit next to each other.

 Posted by Charlie on 2013-02-25 14:55:08

 Search: Search body:
Forums (0)