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 Age Ascertainment III (Posted on 2013-03-19)
1. When completed, this crossnumber puzzle has exactly one digit in each box.
2. None of the a,b,c or d boxes (whether down or across) can contain any leading zero.
3. Both concatenations ab and cd consist of nonzero digits.
```       +-----+-----+
|  a  |  b  |
+-----+-----+-----+
|  c  |     |     |
+-----+-----+-----+
|  d  |     |
+-----+-----+

ACROSS                                         DOWN

a. Abigail's age                           a. Sum of three of the ages
in c "across".
c. Sum of Abigail's age,
Blanche's age, Cynthia's                   b. Cynthia's age.
age, and Darlene's age.
c. Darlene's age.
d. Blanche's age
```
Whose age was omitted in a "down" category?

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 computer solution Comment 1 of 1

CLS
FOR abi = 10 TO 99
FOR bla = 10 TO 99
FOR cyn = 10 TO 99
FOR dar = 10 TO 99
ab\$ = LTRIM\$(STR\$(abi))
IF RIGHT\$(ab\$, 1) <> "0" THEN
bl\$ = LTRIM\$(STR\$(bla))
cy\$ = LTRIM\$(STR\$(cyn))
da\$ = LTRIM\$(STR\$(dar))
IF RIGHT\$(da\$, 1) <> "0" AND RIGHT\$(da\$, 1) = LEFT\$(bl\$, 1) AND RIGHT\$(ab\$, 1) = LEFT\$(cy\$, 1) THEN
tot = abi + bla + cyn + dar
IF tot > 99 AND tot < 1000 THEN
t\$ = LTRIM\$(STR\$(tot))
IF LEFT\$(t\$, 1) = LEFT\$(da\$, 1) AND RIGHT\$(t\$, 1) = RIGHT\$(cy\$, 1) THEN
aDown\$ = LEFT\$(ab\$, 1) + MID\$(t\$, 2, 1) + RIGHT\$(bl\$, 1)
IF aDn = tot - abi OR aDn = tot - bla OR aDn = tot - cyn OR aDn = tot - dar THEN
PRINT " "; ab\$
PRINT t\$
PRINT bl\$;
SELECT CASE tot
PRINT "   Abigail"
PRINT "   Blanche"
PRINT "   Cynthia"
PRINT "   Darlene"
END SELECT
PRINT
END IF
END IF
END IF
END IF
END IF
NEXT
NEXT
NEXT
NEXT

finds

` 1620095   Blanche`

 Posted by Charlie on 2013-03-19 14:36:14

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