what is the value of [(4-a)/a]6
We know that x^3 + y^3 = (x+y)(x^2-xy+y^2)So, for (x,y)=(3^1/3, 1), we have:
4 = a*(3^1/3 + 1)
=> (3^1/3 + 1) = 4/a
=> [(4-a)/a] = 3^1/3
=> [(4-a)/a]^6 = (3^1/3)^6 = 3^2 = 9
Edited on January 19, 2013, 11:17 am
blackjack
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flooble's webmaster puzzle
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