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 The 73rd digit (Posted on 2013-01-29)
a = 111...111 (a string of 2012 ones)

What is the 73rd digit from the end of a2?

 No Solution Yet Submitted by Danish Ahmed Khan No Rating

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 computer solution | Comment 2 of 3 |

list
10   A=(10^2012-1)//9
20   B=modpow(A,2,10^73)
30   print B\10^72
OK
run
0

showing zero as the answer.

The last 74 digits are:

?modpow(A,2,10^74)

20987654320987654320987654320987654320987654320987654320987654320987654321

 Posted by Charlie on 2013-01-29 12:07:59
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