A friend presented an easy puzzle to me:
"Given the digits 2 3 4 5 6 , insert 4 mathematical operators between them, do not change the order and get 10 as a result."
My solution was (2^3+4)*5/6 to which my friend reacted by:
"Exponentiation is not permitted, use just the 4 arithmetical operations (or less) and not more than one pair of brackets."

I've found a solution and dare you to find it or maybe find other solutions as well.

2+3+4-5+6

Posted by Charlie on 2012-12-28 10:50:34