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Just arithmetic signs (Posted on 2012-12-28) Difficulty: 2 of 5
A friend presented an easy puzzle to me:
"Given the digits 2 3 4 5 6 , insert 4 mathematical operators between them, do not change the order and get 10 as a result."
My solution was (2^3+4)*5/6 to which my friend reacted by:
"Exponentiation is not permitted, use just the 4 arithmetical operations (or less) and not more than one pair of brackets."

I've found a solution and dare you to find it or maybe find other solutions as well.

See The Solution Submitted by Ady TZIDON    
Rating: 2.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts More solutions | Comment 9 of 10 |

Exponentiation - superscripting to the right - is noted as not being permitted, but nothing was said about subscripting to represent different bases:

2 + 34 + 56 = 10   (note: 34 = 3 and  56 = 5)
234 + 5 - 6 = 10   (note: 234 = 2*41 + 3*40 = 11)

As exponentiation is not permitted, I have assumed 'iterated exponetiation', i.e., tetration, is also excluded, else the following could be a solution:
(2^^3 + 4) / 5 + 6  = 10 (note: 2^^3 = 222= 16,
^^ represents a single operator for tetration in ASCII notation)


  Posted by Dej Mar on 2013-01-06 07:36:10
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