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Prime Mean (Posted on 2013-04-17) Difficulty: 3 of 5
At the end of a soccer season, every player on a team scored a prime number of goals, and the average for the team as a whole was also a prime number. No playerís tally was equal to anotherís, and no playerís tally was the same as the average.

Given that nobody scored more than 45 goals, how many goals did each player score?

*** There are 11 players in a soccer team.

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (3 votes)

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Solution the computer method | Comment 3 of 5 |

The largest prime not exceeding 45 is the 14th prime, 43, so to get the total of all the players' scores we just need the total of the first 14 primes and subtract out three of these primes.  
   10      for I=1 to 14:First14=First14+prm(I):next
   20      for LeaveOut1=1 to 12
   30        for LeaveOut2=LeaveOut1+1 to 13
   40          for LeaveOut3=LeaveOut2+1 to 14
   90             Sum=First14-prm(LeaveOut1)-prm(LeaveOut2)-prm(LeaveOut3)
  100             Avg=Sum//11
  110             if Avg=int(Avg) then if prmdiv(Avg)=Avg then
  120                  :if Avg=prm(LeaveOut1) or Avg=prm(LeaveOut2) or Avg=prm(LeaveOut3) then
  150                  :for I=1 to 14
  160                   :if I<>LeaveOut1 and I<>LeaveOut2 and I<>LeaveOut3 then
  170                             :print prm(I);:endif
  180                  :next
  190                  :print:print Avg
  200      next:next:next

which finds these individual players' scores

 5  7  11  13  17  19  29  31  37  41  43
which average


  Posted by Charlie on 2013-04-17 12:37:57
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