The natural numbers a,b,c,d are such that their least common multiple equals a+b+c+d. Prove that abcd is divisible by 3 or by 5.
(In reply to
re(2): Proof by Steve Herman)
I agree that it is a splendid result.
I started out with just the same idea, but failed to complete the connection between the sets. It seems I was looking through the wrong end of the telescope!
Bravo indeed, Math Man!
Edited on May 11, 2013, 12:35 am
|
|
Posted by broll
on 2013-05-11 00:31:28 |
re(3): Proof
