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Cubic Equation (Posted on 2013-06-09) Difficulty: 4 of 5
Determine all triplets (a,b,c) of nonzero integers satisfying:
987654321*a + 123456789*b + c = (a + b + c)3

Prove that there are no others.

No Solution Yet Submitted by K Sengupta    
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Question re: A second all-positive solution (spoilers) | Comment 5 of 13 |
(In reply to A second all-positive solution (spoilers) by Charlie)

How about trying advancing a,b,c by step=50 and looking for justification later?

BTW , my  "pifometer" guess  is a+b+c=30000 might be your next solution, just find the a,b,c triplet

Edited on June 10, 2013, 3:15 am
  Posted by Ady TZIDON on 2013-06-10 03:06:20

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