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Card Deal (Posted on 2013-06-20) Difficulty: 2 of 5
A selection of eight cards is dealt with every second card being returned to the bottom of the pack. Thus the top card goes to the table, card two goes to the bottom of the pack, card three goes to the table, card four to the bottom of the pack, and so on. This procedure continues until all cards are dealt.

The order in which the cards appear on the table is:
   
           A K A K A K A K
How were the cards originally stacked?

No Solution Yet Submitted by K Sengupta    
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Solution re: What if...SPOILER -- general solution and Ady's question | Comment 2 of 3 |
(In reply to What if...SPOILER by Ady TZIDON)

If the cards in the original pack are numbered 1 through 8, we can see where they end up:

Table      Pack
12345678

1        3456782
13         567824
135        78246
1357       2468
13572      684
135726     48
1357264    8
13572648

So whatever card you want to come out first should start off first; whatever card you want second should start out third, etc.

So to answer Ady's question:

AcKcAdKdAhKhAsKs
1 3 5 7 2 6 4 8

the original sequence traces back those numbers:

AcAhKcAsAdKhKdKs


  Posted by Charlie on 2013-06-20 11:16:51
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