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 Commemorations (Posted on 2013-02-06)
3 jealous brothers are to divvy up a set of commemorative coins.

There are an equal number of coins of each of the values: \$1, \$2, \$3.

They discover that it is possible to do this in such a way that each brother gets a different assortment of coins, yet each gets the same number of coins and the same total value of coins.

What's the smallest possible number of coins in the set?

 No Solution Yet Submitted by Jer Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(2): A misread? Comment 7 of 7 |

Charlie posted:

`perden    total  \$1 \$2 \$3      \$1 \$2 \$3      \$1 \$2 \$36       18     1  4  1       2  2  2       3  0  3..............9       27     2  5  2       3  3  3       4  1  4`
`With a small edit this is mine:9      (27)   (2  5  2)     (3  3  3)     (4  1  4)  \$18I did not have the total coins (27) or the value of each share (\$18) in my previous post.`

Edited on February 7, 2013, 12:09 am
 Posted by brianjn on 2013-02-07 00:08:13

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