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Fun sequence (Posted on 2013-03-01) Difficulty: 2 of 5
1, 3, 10, 33, 109, ?...

No Solution Yet Submitted by Math Man    
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Solution ?... SPOILER Comment 1 of 1


The solution can be obtained either:

a) by assuming recurrence like a(n)=A*a(n-1)+B*a(n-2)+C
    & evaluating A,B,C from the given members of the "fun (?)" seq.

b)  check-in  @ OEIS

  Posted by Ady TZIDON on 2013-03-01 17:52:44
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