Determine all possible pairs (x,y) of
halfintegers, with x ≤ y, that satisfy this equation:
[x
^{2}] + [y
^{2}] = 2016
Prove that there are no others.
*** [x] denotes the greatest integer ≤ x.
(In reply to
re: computer solution by broll)
Of the 16 WolframAlpha solutions, only half have x <= y. The only two that my list failed to include were two cases where both x and y were negative:
x=85/2, y=29/2
x=71/2, y=55/2
So there are actually 8 solutions.

Posted by Charlie
on 20130801 09:41:59 