Find the probability that if each of the digits 0, 1, 2, ..., 9 be placed exactly once in random order in the blank spaces of:
the resulting number will be divisible by 396.
(In reply to re: spoiler, hopefully
by Math Man)
REM: unless I've erred in my hasty addition.
I've checked my addition twice, but not the subtraction, my
result was 1 instead of 11.
I must admit that it was immediately clear that only divisibility by
11 mattersl and that the final result must be either zero or 1, since adding 45 ( to even places only) is independent of the addends