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Number machine problem 1 (Posted on 2003-06-08) Difficulty: 1 of 5
I have a number machine. I say x gives y if when x goes in, y comes out. For any numbers x and y, by "xy" I mean x followed by y. Here are my two rules.

1x gives x.
For example, 13 gives 3.
If x gives y, then 2x gives yy.
For example, 213 gives 33 since 13 gives 3.

What is a number that gives itself?

See The Solution Submitted by Tim Axoy    
Rating: 3.7000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(3): Solution | Comment 4 of 12 |
(In reply to re(2): Solution by Charlie)

No, that line means the solution.

Because when you combine the statments, you get "21y gives yy", and subtracting a y from both sides, you get "21 gives y", so y must be 21.

When I said 121 gives itself, I mean 121 = x for the second rule. 2 121 = 21 21. I found y, then figured out what x was. Then I could figure out what the number that gives itself.
  Posted by Gamer on 2003-06-08 06:56:20

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