All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Minimum Sum Muse (Posted on 2013-10-16) Difficulty: 3 of 5
Given that:
A + 13*B is divisible by 11 and:
A + 11*B is divisible by 13
whenever, each of A and B is a positive integer.

Determine the minimum value of A+B.

No Solution Yet Submitted by K Sengupta    
Rating: 2.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts possible solution | Comment 1 of 4

a+b=43 is the minimum value.

Let c=11*13 = 143      
      
Then the pair: c+11*c, c+13*c or {1716, 2002} satisfies the stipulation, when a=b=143. So a 'minimum value' if such exists, must be less than 286. Using WolframAlpha,

(a+13b) = 11m, (a+11b) = 13n, 0<a<b, (a+b)<286 quickly produces a list that includes: {a = 13,   b = 65,   m = 78,   n = 56}

Using (a+13b) = 11m, (a+11b) = 13n, 0<a<b, (a+b)<78 confirms that {a = 20,   b = 23,   m = 29,   n = 21} is a minimum.

Note: The above fails to take into account that b might be less than a, see succeeding posts.

Edited on October 17, 2013, 3:32 am
  Posted by broll on 2013-10-16 12:56:00

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information