All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Some Powers Sum 2008 (Posted on 2013-11-08) Difficulty: 3 of 5
N is an integer ≥ 2 and each of X, Y and Z is a positive integer with X ≤ Y ≤ Z

Determine all possible solutions to this equation :

XN + YN + ZN = 2008

Extra Challenge: Solve this puzzle without using a computer program.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
more results | Comment 2 of 3 |
2008 = 44^2 +  6^2 +  6^2 
2008 = 42^2 +  12^2 +  10^2 
2008 = 36^2 +  26^2 +  6^2 
2008 = 30^2 +  28^2 +  18^2 


2008 = 2^3 + 10^3 + 10^3 = 4^3 + 6^3 + 12^3 

  Posted by Benny on 2013-11-08 17:21:00
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information