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Perfectly Harmonic (Posted on 2013-11-13) Difficulty: 3 of 5
Each of the three positive integers (81+K), (162+K) and (337+K) is a perfect square such that their positive square-roots are in harmonic sequence.

Determine the value of K, and prove that no other value for K is possible.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Some Thoughts re(2): Solution Comment 3 of 3 |
(In reply to re: Solution by Math Man)

If n=0, then K=-81, so K+81=0 is a square

0 is not a  positive integer.

  Posted by Ady TZIDON on 2013-11-15 02:57:11
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