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Circular Billiards Table (Posted on 2013-04-23) Difficulty: 3 of 5

Given a circular billiards table with center O,
radius r, and no pockets. A cue ball (with a
radius negligible compared to r) is placed at
point A such that 0<|OA|≤r. The ball is struck
and bounces off the cushion twice before
returning to point A.

How was the direction of the shot determined?

See The Solution Submitted by Bractals    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Playing with Geometers' Sketchpad -- a method Comment 6 of 6 |
(In reply to re: Playing with Geometers' Sketchpad -- a method by Charlie)

I'd rater a construction of a solution but this is the best I can do so far.

I solved it in a similar way myself but I don't have the notebook with me so I'll derive the solution from what you have.

Just finishing what you started.
You want sinθ/ cos(2θ) = |OA| which I will call D.
sinθ / (1-2(sinθ)) = D
sinθ = D - 2D(sinθ)
2D(sinθ) + sinθ - D = 0 which is quadratic in sinθ

sinθ = (-1 √(1-4*2D*-D))/(2*2D) = (-1√(1+8D))/(4D)

θ = sin^-1 [(-1 √(1-4*2D*-D))/(2*2D)]

90 - 2θ = 90 - 2sin^-1 [(-1 √(1-4*2D*-D))/(2*2D)]

which is consistent with your table.

  Posted by Jer on 2013-04-24 12:49:34

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