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Seven Multiple Muse (Posted on 2013-12-23) Difficulty: 3 of 5
Fill up the the 20 empty boxes in the figure shown below, using the 10 base ten digits 0,1,2,3,4,5,6,7,8,9 each occurring exactly twice such that:

(a) Each horizontal number is a multiple of 7.
(b) Each vertical number is a multiple of 7.
(c) The total sum of all the horizontal and vertical numbers is the maximum of all such arrangements satisfying both (a) and (b).
            +---+
            |   |   
        +---+---+---+
        |   |   |   |          
    +---+---+---+---+---+
    |   |   |   |   |   |  
+---+---+---+---+---+---+---+
|   |   |   |   |   |   |   |
+---+---+---+---+---+---+---+
|   |   |           |   |   |
+---+---+           +---+---+ 
Note: As the figure shows, the bottom row should be considered as two 2-digit numbers rather than a single 4-digit number.

  Submitted by K Sengupta    
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Solution: (Hide)
The arrangements are:

Either:
      
       7      
     3 4 3    
   2 7 6 0 1  
 9 9 8 2 8 0 5
 1 4       5 6
Or:
       7      
     3 4 3    
   2 7 6 0 8  
 9 9 8 2 1 0 5
 1 4       5 6
each of them yielding a maximum sum of 10019520.

For an explanation, refer to Charlie's solution here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solutioncomputer solutionCharlie2013-12-23 23:28:37
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