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Distance to Diagonal (Posted on 2013-05-14) Difficulty: 2 of 5


Let ABCD be a parallelogram with ∠BAC = 45° and ∠ABD = 30°.

What is the distance from B to diagonal AC in terms of the
lengths of sides AB and AD?

See The Solution Submitted by Bractals    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Simple Trigonometry (spoiler) | Comment 2 of 6 |
(In reply to Simple Trigonometry (spoiler) by Steve Herman)

Wow.   I didn't see it as quite so simple.

I instead solved by finding AO, then the area of triangle BAO, then working backwards from this triangle to find its altitude.

It turns out to be AB*sin(45).
In general the distance is AB*sin(∠BAC)

∠ABD and the length of AD are not independent, nor are they so simple.

  Posted by Jer on 2013-05-14 16:01:20

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