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 A G E S III (Posted on 2013-06-11)
"…My age now is twice your age when I was your present age .
On the other hand - when your age in the future will equal my present age, and hopefully both of us will be alive, sum of both our ages will total 63 yrs. …"

In integer values – find their "current" ages.

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 What's the difference? (spoiler) Comment 1 of 1
Let the difference in their ages be d.
The younger one is x years old and the older one is x + d.

d years ago, the ages were (x - d) and x
d years from now, the ages will be (x + d) and (x + 2d)

So
(x + d) = 2* (x - d)      (statement 1)

(x+d) + (x + 2d) = 63  (statement 2)

Solving, x = 21 and d = 7

So the "current" ages are 21 and 28.

7 years ago the ages were 14 and 21, and 28 is in fact twice 14
7 years from now the ages will be 28 and 35, which sum to 63.

Edited on June 11, 2013, 11:34 am
 Posted by Steve Herman on 2013-06-11 10:38:44

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