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Any others? (Posted on 2013-06-18) Difficulty: 2 of 5
100 is a square which is also a sum of 4 consecutive cubes.
Are there any others?

No Solution Yet Submitted by Ady TZIDON    
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re: No Subject | Comment 8 of 9 |
(In reply to No Subject by xdog)

xdog,

Evaluating:

(2x+3) = a^2 and (x^2+3x+6) = 2b^2 for x=0: a=b=3^(1/2)
(and c=2*3^(1/2), so 2c^2 - 15 = 9)

(2x+3) = a^2 and (x^2+3x+6) = 2b^2 for x=1: a=b=5^(1/2)
(and c=2*5^(1/2)), so 2c^2-15 = 25)

it seems it can't be assumed that a,b,c, are integers.

Edited on June 22, 2013, 1:57 am
  Posted by broll on 2013-06-22 01:23:06

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