All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Any others? (Posted on 2013-06-18) Difficulty: 2 of 5
100 is a square which is also a sum of 4 consecutive cubes.
Are there any others?

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
reply to broll Comment 9 of 9 |
(In reply to re: No Subject by broll)

There's no assumption.  You're mixing cases.  My demonstration was for gcd of the expressions = 1 but for x=0, gcd=3 and for x=1, gcd=5.

In the first case the equation to be evaluated is 3a^4 + 5 = 8b^2 and in the second it's 5a^4 + 3 = 8b^2.

For completeness, gcd=15 requires 15a^4 + 1 = 8b^2.



  Posted by xdog on 2013-06-22 09:58:53
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information