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Four Equal Triangles (
Posted on 20130616
)
Here's a problem I found in the Problems section of a
math journal. The way I read it, it is not true.
Let ABCD be a convex quadrilateral. Prove that
there exists a point P inside ABCD such that
[PAB]=[PBC]=[PCD]=[PDA],
if and only if
the diagonals bisect each other.
Here [XYZ] denotes the area of triangle XYZ.
See The Solution
Submitted by
Bractals
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re: Solution
 Comment 2 of 3 
(In reply to
Solution
by Jer)
I arrived at the same conclusion.
What about restating the problem by replacing
"the diagonals bisect each other"
with
"at least one diagonal bisects the other"?
Posted by
Bractals
on 20130617 13:56:07
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