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Seven - with and without (Posted on 2013-08-09) Difficulty: 2 of 5
Let us divide a set of all n-digit numbers into two subsets:
N7- whose members contain at least one 7 and Nw - whose members are 7-free ,e.g. for n=2 there are 18 members in N7: 17,27,37,... 70, 71,72, …79, and there are 72 members in Nw.
Let us denote those quantities by q7 and qw: q7(2)=18 and qw(2)=72.

Evaluate q7(n) and qw(n) for the following values of n:

n=5
n=42
n=100

No Solution Yet Submitted by Ady TZIDON    
Rating: 3.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Equality | Comment 4 of 6 |
Thanks for doing the heavy lifting, Charlie.

I note that q7(n) and qw(n) are most nearly equal when n = 6 or 7.

n = 6  427608 / 472392   = .905
n = 7  4748472 / 4251528 = 1.116


  Posted by Steve Herman on 2013-08-09 14:49:23
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