All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Maximizing product (Posted on 2013-09-19) Difficulty: 3 of 5
In a triangle ABC two items are defined : the side AB=c and the height from point C to this side Hc= k.

What is the maximum value of the product Ha*Hb* Hc ?

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
corrected solution | Comment 3 of 4 |
Steve, you are correct, so here is the full solution covering all situations :
The need to maximize Sin(Gamma) remains correct, except for the fact that if k>c/2, Gamma cannot be assumed as 90 deg. so we must calculate Sin(Gamma) and maximize it:
Assume a triangle ABC where a=b, and draw a parralel to c going through point C, at which we observe angle Gamma1.
We now shift point C along the parralel a distance f in the direction of A, thus obtaining a triangle ABD with angle Gamma2.
Denoting :  c/2=e, we get the following :
both triangles ABC and ABD have equal areas:

Sin(Gamma2)=2*e*k/(AD*BD)=2*e*k/[sqrt(k^2+(e-f)^2)*sqrt(k^2+(e+f)^2) ]

For maximizing Sin(Gamma), it is needed to minimize the denominator of Sin(Gamma2) by means of changing f :-

denominator^2 = [k^2+(e-f)^2]*[k^2+(e+f)^2] =
                          (k^2+e^2)^2 + f^2*[2*(k^2-e^2)+f^2]

We distinguish now 2 cases :-

   a.  k>e

      minimization is achieved by  f=0
 and we get the max. Sin(Gamma) for the case of a=b and Sin(Gamma) = 2*e*k/(k^2+e^2)
and therefore :
                         Ha*Hb*Hc = c*k*Sin(Gamma) =

   b. k<e

      The minimal denominator will be reached for : f^2=e^2-k^2
       for which :-
                         Sin(Gamma2)=2*e*k/(2*e*k) =1
                    Ha*Hb*Hc = k*c^2

  Posted by Dan Rosen on 2013-09-24 13:53:13
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information