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 Two cars, three towns (Posted on 2013-10-07)
Two cars on Crete left towns of Knossos and Phaistos at the same time to drive to the other town, passing each other at Gortyns and both travelling at different steady speeds.

The car from Knossos completed the journey from Gortyns to Phaistos in 45 minutes at a steady speed of 64 km/h.

The car from Phaistos completed the journey from Gortyns to Knossos in 20 minutes.

Find the speed of the car from Phaistos.

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 solution if I did the algebra right | Comment 1 of 3

As speed is given in km/h, time is best measured in hours.

The distance between Knossos and Phaistos is the sum of the two parts of the journey: K to G and G to P, regardless of the order.

If x is the number of hours from the time they started out until they met at Gortyns, then

64*(3/4 + x) km = (1/3 + x)*s km

where s is the speed of the car from Phaistos.

And the distance between G and P:

3/4 * 64 = x * s

x = 48 / s

then

48 + 3072/s = (1/3 + 48/s) * s

48 + 3072/s = s/3 + 48

s^2 = 3*3072 = 9216

s = 96 km/h

 Posted by Charlie on 2013-10-07 17:28:46

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