Below are four groups of three numbers each.
Combine the numbers in each group using only addition, subtraction, division, exponentiation, factorials and brackets so that each triplet yields the same result (there might be several solutions):
Inspired by "e pluribus unum" 2003 & 2004.
(In reply to Not the way you intended.
Although your D1 solution might be fitting the "brackets" formal
definition -I referred to parenthesis ((())) to justify the D3.
Do not give up - try again...