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No multiplication allowed (Posted on 2013-10-17) Difficulty: 3 of 5
Below are four groups of three numbers each.

Combine the numbers in each group using only addition, subtraction, division, exponentiation, factorials and brackets so that each triplet yields the same result (there might be several solutions):

a. 2,7,8
b. 2,5,26
c. 3,11,15
d. 3,49,71

Inspired by "e pluribus unum" 2003 & 2004.

See The Solution Submitted by Ady TZIDON    
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Comments: ( Back to comment list | You must be logged in to post comments.)
re: 3/4 of the way (In two ways) Want a hint? Comment 8 of 8 |
(In reply to 3/4 of the way (In two ways) by Brian Smith)

A20 SEEMS IMPOSSIBLE.

D6- YOU WERE VERY CLOSE- consider (3!)!


  Posted by Ady TZIDON on 2013-10-22 18:54:24
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