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 No multiplication allowed (Posted on 2013-10-17)
Below are four groups of three numbers each.

Combine the numbers in each group using only addition, subtraction, division, exponentiation, factorials and brackets so that each triplet yields the same result (there might be several solutions):

a. 2,7,8
b. 2,5,26
c. 3,11,15
d. 3,49,71

Inspired by "e pluribus unum" 2003 & 2004.

 Submitted by Ady TZIDON No Rating Solution: (Hide) Full solution A: 2*7-8 = 6 B: 2^5-26 = 6 C: 11-15/3 = 6 D: ((3!))/(71+49) = 720:120=6 3 out of 4 : A: to get 20 seems impossible B: 26-(5-2)! = 20 C: 15+11-3! = 20 D: (71+49)/3! = 20 also A: (8-7)^2 = 1 B: 26-(5^2) = 1 C: 15-11-3 = 1 D: to get 1 seems impossible

 Subject Author Date re: 3/4 of the way (In two ways) Want a hint? Ady TZIDON 2013-10-22 18:54:24 3/4 of the way (In two ways) Brian Smith 2013-10-22 11:33:05 Which one do you miss? Ady TZIDON 2013-10-21 18:31:43 HINT: releasing the target number Ady TZIDON 2013-10-19 18:48:29 re: Just one instance? Ady TZIDON 2013-10-19 18:14:32 Just one instance? Larry 2013-10-19 15:38:28 re: Not the way you intended.-(brackets) Ady TZIDON 2013-10-17 19:10:09 Not the way you intended. Jer 2013-10-17 15:48:58

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