(In reply to
Another approach by Steve Herman)
I used Steve Herman's other approach doing a very tedious long division.
The final remainder was:
(11a + 22)x + (12a  219 + b)
Which leads to:
a=2
b=243
which agrees with the first solution, by Daniel.
Also, in the quotient obtained by long division, the coefficients for the powers higher than x^3 came out just as in Daniel's solution. After that:
(a+10)x^3 + (132a)x^2 + (a56)x + (4a+73) i.e. with same answer, only in terms of "a"

Posted by Larry
on 20130804 20:05:43 