(In reply to Another approach
by Steve Herman)
I used Steve Herman's other approach doing a very tedious long division.
The final remainder was:
(-11a + 22)x + (-12a - 219 + b)
Which leads to:
which agrees with the first solution, by Daniel.
Also, in the quotient obtained by long division, the coefficients for the powers higher than x^3 came out just as in Daniel's solution. After that:
(a+10)x^3 + (13-2a)x^2 + (a-56)x + (4a+73) i.e. with same answer, only in terms of "a"
Posted by Larry
on 2013-08-04 20:05:43