perplexus.info :: Numbers : As easy as 123

As easy as 123 (Posted on 2013-10-25)

In the multiplication of two 3-digit numbers, all digits Except 1,2, and 3 were either erased or were not initially a part of the process.

Fill in the missing digits if 3EE*EEE=2E11E1 and the partial products (in some order) were: 2EE2, 2EE3, and 3321.

See The Solution Submitted by Ady TZIDON

No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)

Solution/spoiler

Comment 1 of 1

The first partial product has to be 3321 to give 1 as the last digit of the answer.

3321 = 9*369 making 369 the first multiplier.

7*369 = 2583 and 8*369 = 2952 are the only multiples ending in 2 and 3 but 879*369 doesn't match the problem conditions, so the answer is:

369

789

---

3321

2952

2583

------

291141

Posted by xdog on 2013-10-25 10:51:22

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (16)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info